Does 1=0 ?

Writes simon on April 21st, 2008

Read More: Science & Technology

Say x=y

Therefore

x2 = xy.

So if you take the same from both sides.

x2 - y2 = xy - y2.

Now divide both sides by  (x-y)

We get

x + y = y

Now as x=y we can say.

2y=y

Divide by y

We get 2=1

Subtract 1from both we get

1=0.

So what is the problem with the proof? Answer tomorrow

3 Responses to “Does 1=0 ?”

  1. 0 Tuathal

    Is the problem that by dividing by x-y you are in fact dividing by zero?

  2. 0 simon

    bingo

  3. 0 Richie

    x=y, then x-y=0. Also halfway through you divided by (x-y). So that’s where you went wrong

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